Respuesta :

Louli
Answer:
[tex] \frac{25-y^2}{16} + \frac{y^2}{9} = 1[/tex]

Explanation:
For the first given equation, we will need to isolate the x². This can be done as follows:
x² + y² = 25
x² + y² - y² = 25 - y²
x² = 25 - y² ..................> I

For the second given equation:
We will remove every x² and substitute with its equivalence from I as follows:
[tex] \frac{x^2}{16} + \frac{y^2}{9} = 1[/tex]

[tex] \frac{25-y^2}{16} + \frac{y^2}{9} = 1[/tex]

Hope this helps :)

It is the c)25-y^2-y^2 by 16-9 = 1

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