04-04-2018
Mathematics

contestada

solve for the exact value(s) of x, 0
2sin2xcosx + sin2x = 0

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mkryukova19 mkryukova19

04-04-2018

sin2x (2cosx+1)=0
sin2x=0
2x=πn, n=0,1,2...
x=(π/2), 3π/2
2cosx=-1
cosx=-1/2
x=arccos(-1/2)
x=2π/3, 4π/3

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