LuqmanulHakim LuqmanulHakim
  • 01-01-2018
  • Mathematics
contestada

can someone proove it to me
thank you for your help

can someone proove it to me thank you for your help class=

Respuesta :

Hosein
Hosein Hosein
  • 01-01-2018

[tex] \sin(2x + x) = \sin(2x) \cos(x) + \\ \cos(2x) \sin(x) = 2 \sin(x) { \cos(x) }^{2} \\ + \sin(x) { \cos(x) }^{2} - { \sin(x) }^{3} = \\ 3 \sin(x) { \cos(x) }^{2} - { \sin(x) }^{3} = \\ 3 \sin(x) - 3 { \sin(x) }^{3} - { \sin(x) }^{3} = \\ 3 \sin(x) - 4 { \sin(x) }^{3} [/tex]
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