The surface area of the smaller solid is found to be 214 square meters.
The surface area is given as the sum of the area of all the faces of a three-dimensional object.
The same shape has equivalent ratio of the surface area to volume. It is given as:
[tex]\rm \dfrac{\sqrt{area_1}}{\sqrt{area_2}}=\dfrac{\sqrt[3]{Volume_1} }{\sqrt[3]{Volume_2} }[/tex]
On considering the power of 6 at both the sides of the equation:
[tex]\rm \dfrac{area_1^2}{area_2^2}=\dfrac{volume_1}{volume_2}[/tex]
Considering area 1 and volume 1 for the larger solid, and area 2 and volume 2 for the smaller solid, substituting the values give:
[tex]\rm\dfrac{(856\;m^2)^3}{(area_^2)^3}=\dfrac{(1680\;m^3)^2}{(210\;m^3)^2}[/tex]
By solving the above equation, the area of the smaller solid is found as 214 square meters. Thus, option B is correct.
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