Dimajago
Dimajago Dimajago
  • 03-07-2020
  • Mathematics
contestada

What is the remainder when the product of the 5 smallest prime numbers is divided by 42?

Respuesta :

EpicMinion900 EpicMinion900
  • 03-07-2020

Answer:

21

Step-by-step explanation:

The 5 smallest prime numbers are 1, 2, 3, 5, and 7.

So when multiplied it equals 105.

Divide by 42 and you get 2 21/42

So you have a remainder of 21

Answer Link

Otras preguntas

list in order the three major parts of a greek play
If if takes 3 mins to sew 1in, how many mins will it take to sew 9ft?
what happened during the Russian revolution
Sullen is to moody as monotonous is to what?* attractive drab repetitious varied
Spoken word and written text are different because?
The northwest ordinance of 1787 set a precedent for other western territories by
Dory can run 3.25 miles every hour
Factor the expression using GCF 20p-60=___
Work out the area of a triangle of bass 12 cm and height 7 cm
lm how many times does 177 go into 4