Dimajago Dimajago

03-07-2020
Mathematics

contestada

What is the remainder when the product of the 5 smallest prime numbers is divided by 42?

Respuesta :

09pqr4sT 09pqr4sT

03-07-2020

Answer:

0

Step-by-step explanation:

The five smallest prime numbers are 2, 3, 5, 7 and 11.

2 × 3 × 5 × 7 × 11

= 2310

Divide by 42.

2310/42

= 55, Remainder 0

Answer Link

Otras preguntas

List the sugar and the base found in molecules of atp.

Which of the following would be the correct form of the equation 10t² - 29t = -10 to be able to solve using the zero product property? t(10t - 29) = -10 (2t - 5

which expression is equivalent to (84+16)

What are the three main organs of seed plants

(6CQ) Evaluate the limit, or state that the limit does not exist. 2n+7n/13n

You add 500ml of water at 10celsius to a 100ml of water at 70 Celsius. What is the most likely final temperature of the mixture? A.10c B.20c C.80c D.60c

Show all work and explain in words Findthe value of x. Then find the measure of each labeled angle.

Given that (x, y) = (5, 10), find r.a.2√5b.5√2c.5√5d.5√10

which of the following is a search engine

The set of ordered pairs in the mapping below can be described as which of the following? x----y0 - 83 - 26 - -1(1) a relation only(2) a function only(3) both a